Unlock AI power-ups — upgrade and save 20%!
Use code STUBE20OFF during your first month after signup. Upgrade now →

By Ingeniosos
Published Loading...
N/A views
N/A likes
Causes of Normal and Shear Stresses in Beams
📌 Normal stresses () are perpendicular to the cut face, while tangential (shear) stresses () lie within the plane.
📏 Normal stresses are caused by axial stress (constant across the section, ) or bending moment ($M$, resulting in a stress gradient ).
⚙️ Shear stresses are primarily generated by shear force ($V$, maximum at the center of the section) or torsional moment ($T$, maximum at the outer fiber).
Calculation of Normal Stresses
📐 Bending moment creates a stress profile that varies linearly from zero at the neutral axis (passing through the centroid) to maximum tension and compression at the outer fibers.
➕ Total normal stress in a section is the superposition of the axial stress and the stresses induced by all applied moments ().
⬆️ The most critical position experiences the summation of tensile stresses (e.g., the upper-left corner when both moments and axial load cause tension there).
Calculation of Shear Stresses and Neutral Axis Shift
〰️ Shear stress () due to shear force ($V$) is zero at the outer edges and maximum at the center, calculated using (where $Q$ is the first moment of area).
🌀 Torsional shear stress is proportional to the distance from the center and is maximum at the outer boundary.
⬇️ When both axial force and bending moment () are present, the neutral axis shifts away from the side experiencing net tension. The new neutral axis position ($y$) can be found by setting the total normal stress to zero: .
Key Points & Insights
➡️ Superposition Principle is crucial: Total stress at any point is the algebraic sum of stresses generated by axial load, bending moments (about both axes), and torsion.
➡️ For a rectangular beam under shear, the maximum shear stress occurs at the center and is equal to $1.5$ times the average shear stress ($V/A$).
➡️ The neutral axis under combined loading is located where the normal stress () is zero; its position shifts based on the relative contributions of the axial load and the bending moments.
➡️ In the provided example, Point 1 (upper corner) was critical due to the summation of tensile stresses from the axial load ($P$) and the moment .
📸 Video summarized with SummaryTube.com on Mar 01, 2026, 04:27 UTC
Find relevant products on Amazon related to this video
As an Amazon Associate, we earn from qualifying purchases
Full video URL: youtube.com/watch?v=MLtOEvCCqwI
Duration: 9:35
Causes of Normal and Shear Stresses in Beams
📌 Normal stresses () are perpendicular to the cut face, while tangential (shear) stresses () lie within the plane.
📏 Normal stresses are caused by axial stress (constant across the section, ) or bending moment ($M$, resulting in a stress gradient ).
⚙️ Shear stresses are primarily generated by shear force ($V$, maximum at the center of the section) or torsional moment ($T$, maximum at the outer fiber).
Calculation of Normal Stresses
📐 Bending moment creates a stress profile that varies linearly from zero at the neutral axis (passing through the centroid) to maximum tension and compression at the outer fibers.
➕ Total normal stress in a section is the superposition of the axial stress and the stresses induced by all applied moments ().
⬆️ The most critical position experiences the summation of tensile stresses (e.g., the upper-left corner when both moments and axial load cause tension there).
Calculation of Shear Stresses and Neutral Axis Shift
〰️ Shear stress () due to shear force ($V$) is zero at the outer edges and maximum at the center, calculated using (where $Q$ is the first moment of area).
🌀 Torsional shear stress is proportional to the distance from the center and is maximum at the outer boundary.
⬇️ When both axial force and bending moment () are present, the neutral axis shifts away from the side experiencing net tension. The new neutral axis position ($y$) can be found by setting the total normal stress to zero: .
Key Points & Insights
➡️ Superposition Principle is crucial: Total stress at any point is the algebraic sum of stresses generated by axial load, bending moments (about both axes), and torsion.
➡️ For a rectangular beam under shear, the maximum shear stress occurs at the center and is equal to $1.5$ times the average shear stress ($V/A$).
➡️ The neutral axis under combined loading is located where the normal stress () is zero; its position shifts based on the relative contributions of the axial load and the bending moments.
➡️ In the provided example, Point 1 (upper corner) was critical due to the summation of tensile stresses from the axial load ($P$) and the moment .
📸 Video summarized with SummaryTube.com on Mar 01, 2026, 04:27 UTC
Find relevant products on Amazon related to this video
As an Amazon Associate, we earn from qualifying purchases

Summarize youtube video with AI directly from any YouTube video page. Save Time.
Install our free Chrome extension. Get expert level summaries with one click.