The video transcript is in Indonesian and discusses a physics problem related to projectile motion (parabolic motion). The summary below is translated and structured into English as required.

Projectile Motion Calculation
📌 The problem involves a ball thrown from a building 15 meters high ($h = 15 \text{ m}$) at an initial velocity ($V_0$) of $20 \text{ m/s}$ at an angle ($\theta$) of $30^\circ$ to the horizontal.
⚙️ The formula used to find the maximum height reached *above the launch point* ($Y_M$) during the parabolic trajectory is $Y_M = \frac{V_0^2 \sin^2 \theta}{2g}$.
🔢 Assuming gravitational acceleration ($g$) is $10 \text{ m/s}^2$, the calculated maximum height *above the building* is $5 \text{ meters}$ ($Y_M = 5 \text{ m}$).

Determining Final Maximum Height
⏫ The required answer is the maximum height measured from the ground surface ($H_{\text{max}}$).
➕ This final height is calculated by adding the building's height to the maximum height gained during the projectile motion: $H_{\text{max}} = h + Y_M$.
✅ The final result for the maximum height above the ground is $20 \text{ meters}$ ($15 \text{ m} + 5 \text{ m}$).

Key Points & Insights
➡️ Identify all given parameters: initial height ($h = 15 \text{ m}$), initial velocity ($V_0 = 20 \text{ m/s}$), and launch angle ($\theta = 30^\circ$).
➡️ Use the standard formula for maximum vertical displacement in projectile motion, $Y_M = \frac{V_0^2 \sin^2 \theta}{2g}$, remembering to use $\sin 30^\circ = 1/2$.
➡️ Always confirm the reference point for the final required measurement; in this case, the total maximum height is the sum of the initial height and the maximum vertical displacement gained.

📸 Video summarized with SummaryTube.com on Oct 11, 2025, 08:01 UTC