The video discusses a physics problem involving projectile motion (gerak parabola) to calculate the time taken to reach maximum height.

Projectile Motion Calculation
📌 The problem asks for the time ($t$) required to reach maximum height given an initial velocity ($V_0$) of 8 m/s and an elevation angle ($\theta$) of 30 degrees.
⏳ The formula used for vertical velocity is $V_y = V_{0y} - gt$, where at maximum height, $V_y = 0$.
📐 The initial vertical velocity ($V_{0y}$) is calculated as $V_0 \sin\theta$: $8 \times \sin(30^\circ) = 8 \times \frac{1}{2} = \mathbf{4 \text{ m/s}}$.
⏱️ Assuming the acceleration due to gravity ($g$) is 10 m/s² (since it wasn't specified), solving $0 = 4 - 10t$ yields a time $t = \frac{4}{10} = \mathbf{0.4 \text{ seconds}}$.

Key Formulas and Assumptions
➕ The vertical component of initial velocity is determined using the sine function: $V_{0y} = V_0 \sin\theta$.
➗ At the peak of the trajectory, the vertical velocity ($V_y$) is momentarily zero.
⚙️ The standard value of gravity ($g$) was assumed to be 10 m/s² for this calculation.

Key Points & Insights
➡️ To find the time to reach maximum height in projectile motion, set the vertical velocity equation to zero ($V_y = 0$).
➡️ Calculate the initial vertical velocity ($V_{0y}$) first, as it is essential for determining the time ($t$).
➡️ The final calculated time required to reach maximum height for the given parameters is 0.4 seconds.

📸 Video summarized with SummaryTube.com on Oct 11, 2025, 07:01 UTC